If α α and β β ( α α < β β ) are the roots of the equation x 2 + bx + c = 0, where c < 0 < b, then
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Given c < 0 < b and α α + β β = - b α α β β = c
from (2), c < 0 ⇒ ⇒ α α β β < 0 ⇒ ⇒ either α α is –ve or β β is –ve and second quantity is positive.
from (1), b > 0 ⇒ ⇒ - b < 0 ⇒ ⇒ α α + β β < 0 ⇒ ⇒ the sum is negative
⇒ ⇒ modules of nengative quantity is > modulus of positive
quantity but α α < β β is given.
Therefore, it is clear that α α is negative and β β is positive and modulus of α α is greater than modulus of β β ⇒ ⇒ α α < 0 β β < | α α |
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